8=y^(-1/2)

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Solution for 8=y^(-1/2) equation: 


D( y )

y = 0

y < 0

y = 0

y = 0

y < 0

y in (0:+oo)

8 = y^(-1/2) // - y^(-1/2)

8-y^(-1/2) = 0

-1*y^(-1/2) = -8 // : -1

y^(-1/2) = 8

-1/2 < 0

1/(y^(1/2)) = 8 // * y^(1/2)

1 = 8*y^(1/2) // : 8

1/8 = y^(1/2)

y^(1/2) = 1/8 // ^ 2

y = 1/64

y = 1/64

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